10x^2+126x-600=0

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Solution for 10x^2+126x-600=0 equation:



10x^2+126x-600=0
a = 10; b = 126; c = -600;
Δ = b2-4ac
Δ = 1262-4·10·(-600)
Δ = 39876
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{39876}=\sqrt{4*9969}=\sqrt{4}*\sqrt{9969}=2\sqrt{9969}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(126)-2\sqrt{9969}}{2*10}=\frac{-126-2\sqrt{9969}}{20} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(126)+2\sqrt{9969}}{2*10}=\frac{-126+2\sqrt{9969}}{20} $

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